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x=2x^2-6(16)
We move all terms to the left:
x-(2x^2-6(16))=0
We get rid of parentheses
-2x^2+x+616=0
a = -2; b = 1; c = +616;
Δ = b2-4ac
Δ = 12-4·(-2)·616
Δ = 4929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{4929}}{2*-2}=\frac{-1-\sqrt{4929}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{4929}}{2*-2}=\frac{-1+\sqrt{4929}}{-4} $
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